theta two. And also we're gonna be addressing for theta one, and also we're gonna speak to it theta c, crucial angle. Let's division both sides by n one here, and also we have sine the the crucial angle climate is the table of contents of refraction that the second medium, which is ice, times sine that the edge of refraction, which is 90 degrees, and divide the by the index of refraction of the early medium, i beg your pardon is water. And sine that 90 is one, and so we'll just say, n 2 over n one here. And also so, the an important angle is the station sine that the index of refraction of ice separated by the table of contents of refraction the water. For this reason that's station sine of 1.309 separated by 1.333, which gives an edge of 79.11 degrees.">

You are watching: Consider the internal reflection of light at the interface between water and ice.

This is college Physics Answers through Shaun Dychko. We want to understand at what minimum angle will we get full internal reflection at the interface in between water and ice. So it"s water here, and ice down listed below here. And, complete internal reflection, that just starts to take place at this vital angle. Strict speaking, crucial angle method the angle of refraction is 90 levels parallel come the interface, and it"s just past that the you get complete internal reflection. So this represents basically the border and also we"ll speak to that the minimum angle such that you obtain this total internal reflection. Snell"s legislation says the the initial index of refraction times sine of the edge of incidence — i beg your pardon is the crucial angle in this case — amounts to the 2nd index that refraction multiply by sine of the angle of refraction. And the angle of refraction is 90 degrees, for this reason that"s theta two. And we"re gonna be solving for theta one, and we"re gonna call it theta c, critical angle. Let"s divide both sides by n one here, and we have sine of the crucial angle then is the table of contents of refraction that the second medium, i m sorry is ice, times sine the the edge of refraction, which is 90 degrees, and also divide that by the index of refraction the the early medium, i beg your pardon is water. And also sine the 90 is one, and so we"ll just say, n two over n one here. And so, the an important angle is the train station sine of the index of refraction the ice divided by the table of contents of refraction that water. For this reason that"s station sine the 1.309 divided by 1.333, which offers an angle of 79.11 degrees.
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