Draw the significant product formed in the following reaction of an epoxide with methoxide in methanol.

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Draw the major product developed in the adhering to reaction of an epoxide through acidic methanol.

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Concepts and reasonThe three-membered cyclic ring include 2 carbon atoms and also 1 oxygen atom is represented as an epoxide. Epoxides are also known as cyclic ethers. The opening of an epoxide follows an attack. An epoxide ring opening counts on the kind of nucleophile present.

FundamentalsIn the presence of a weak nucleophile, the nucleophile attacks an epoxide top top its more substituted site and follows a form reaction. An example for a weak nucleophile is

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In the presence of a strong nucleophile, the nucleophile attacks an epoxide top top a much less substituted site and also follows a kind reaction. An example for weak nucleophile is

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Answer:

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Explanation:Methoxide ion is a strong nucleophile and also it assaults in less substituted site. The opening of epoxide ring take away place and abstracts proton to kind an alcohol product.

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Explanation:In this reaction, the lone pair electrons of oxygen in the epoxide undergo protonation by one acid. Together methanol is much less nucleophilic, it assaults the epoxide in a an ext substituted site and opens the epoxide ring by stability the cation. Then, the cation in oxygen is stabilized by the cleavage the a hydride ion.